Files
PS/leetcode/234.py
Gyubin Han dede0dca01 leetcode
2025-02-19 14:09:55 +09:00

17 lines
457 B
Python

# Definition for singly-linked list.
# class ListNode:
# def __init__(self, val=0, next=None):
# self.val = val
# self.next = next
class Solution:
def isPalindrome(self, head: Optional[ListNode]) -> bool:
l=[]
while not head==None:
l.append(head.val)
head=head.next
for i in range(len(l)//2):
if not l[i]==l[-i-1]:
return False
return True